(x+2)(4x-3)=4x^2-10x+24

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Solution for (x+2)(4x-3)=4x^2-10x+24 equation: 



(x+2)(4x-3)=4x^2-10x+24

We move all terms to the left:

(x+2)(4x-3)-(4x^2-10x+24)=0

We get rid of parentheses

-4x^2+(x+2)(4x-3)+10x-24=0

We multiply parentheses ..

-4x^2+(+4x^2-3x+8x-6)+10x-24=0

We get rid of parentheses

-4x^2+4x^2-3x+8x+10x-6-24=0

We add all the numbers together, and all the variables

15x-30=0

We move all terms containing x to the left, all other terms to the right

15x=30

x=30/15

x=2

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